Example 27

$\;\;\;(6p^{4}q + 1)^2$

$=(A + B)^2 \text{, where } A = 6p^{4}q \text{ and } B = 1 $

$=A^2 + 2AB + B^2$

$=(6p^{4}q)^2 + 2(6p^{4}q)(1) + (1)^2 $

$=36p^{8}q^{2} + 12p^{4}q +1 $